dictionary order

Coding Python Support
1

hi guys,
i don’t know why when i insert some keys and values in a dictionary when i print it shows me inverse order
for example:
dict={}
dict[“a”]=1
dict[“b”]=2
print (dict)
---->{b:2,a:1}
this is an example, and if i run this code it returns me te correct order but my code its a little bit more complicated and i really don’t know why it returns me an inverse list ok keys index.
the questions at this point is, how can i invert the dictionary key index maintaining the correct value?
thx

2

Dicts don’t have an order, lists and tuples do.

Either use a list and put dicts inside if necessary,
maintain a dict + a list of dict keys in the order you need the dict entries,
or use collections.OrderedDict

3

i tried something using collections,OrderedDict but dunno exactly what it means and blender returns me an error, anyway thx for help

4

Read the Python documentation about dictionary, this explains all you probably need to know (including how to get the elements of a dict in a sorted manner using the standard dict implementation):
https://docs.python.org/3.4/tutorial/datastructures.html#dictionaries

5 
from collections import OrderedDict

d = OrderedDict()
d.update({"foo": "123"})
d.update({"bar": "456"})

# foo
# bar
for key in d:
    print(key)

# 123
# 456
for value in d.values():
    print(value)

# Key: foo, Value: 123
# Key: bar, Value: 456
for key, value in d.items():
    print("Key: %s, Value: %s" % (key, value))

# Initialize with key-value pairs (same as above d)
d = OrderedDict( (("foo", "123"), ("bar", 456)) ) # tuple of tuples
d = OrderedDict( [["foo", "123"], ["bar", 456]] ) # list of lists

# Initialize from two sequences, one with keys, one with values (same as above d)
keys = ("foo", "bar")
values = (123, 456)
d = OrderedDict(zip(keys, values))
6

ok thank you